StrBuf::Append( const char * )

Append a null-terminated string to a StrBuf. The string is logically appended to the string pointed to by the StrBuf's buffer.

Virtual?	No
Class	StrBuf
Arguments	const char *buf	pointer to the first byte of the null-terminated string
Returns	void

Notes

The StrBuf's length is incremented by the number of bytes prior to the first null byte in the string.

If the memory for the StrBuf's buffer is not large enough, new memory to contiguously contain the results of appending the null-terminated string is allocated. If new memory is allocated, the old memory is freed. Any memory allocated is separate from the memory for the string.

Example

int main( int argc, char **argv )
{
    char chars[] = "zy";
    StrBuf sb;

    sb.Set( "xyz" );

    cout << "sb.Text() prior to sb.Append( chars ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() prior to sb.Append( chars ) returns ";
    cout << sb.Length() << "\n\n";

    sb.Append( chars );   // append char * to StrBuf

    cout << "sb.Text() after sb.Append( chars ) returns ";
    cout << "\"" << sb.Text() << "\"\n";
    cout << "sb.Length() after sb.Append( chars ) returns ";
    cout << sb.Length() << "\n";
}

Executing the preceding code produces the following output:

sb.Text() prior to sb.Append( chars ) returns "xyz"
sb.Length() prior to sb.Append( chars ) returns 3

sb.Text() after sb.Append( chars ) returns "xyzzy"
sb.Length() after sb.Append( chars ) returns 5