StrRef::Set( char * , int )

Set a StrRef to reference an existing null-terminated string.

Virtual?	No
Class	StrRef
Arguments	char *buf	the null-terminated string to reference
	int len	the length of the string
Returns	void

Notes

StrRef::Set() does not copy the target string; it simply establishes a pointer to it. Be sure that the StrRef pointing to the target string does not outlive the target string.

Example

#include <iostream>

#include <stdhdrs.h>
#include <strbuf.h>

int main( int argc, char **argv )
{
    char chars[] = "xyzzy";
    StrBuf sb;
    StrRef sr;
    sb.Set( chars );
    sr.Set( chars, 3 );

    printf( "chars[] = \"%s\"\n", chars );
    printf( "sr.Text() returns \"%s\"\n", sr.Text() );
    printf( "sb.Text() returns \"%s\"\n", sb.Text() );

    return 0;
}

Executing the preceding code produces the following output:

chars[] = "xyzzy"
sr.Text() returns "xyzzy"
sb.Text() returns "xyz"